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Anndfg
@Anndfg
August 2022
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произведение корней уравнения log_π (x^2+0,1)=0 равно
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MizoriesKun
Verified answer
log_π (x^2+0,1)=0
(x^2+0,1)=π⁰
х²+0,1=1
х²=1-0,1=0,9
х₁;₂=+/-√0,9
х₁*х₂=√0,9*(-√0,9)= -0,9
4 votes
Thanks 3
Anndfg
произведение, а не сумма
MizoriesKun
момент ))
MizoriesKun
обнови страничку
Anndfg
спасибо)))
reshator2000
Verified answer
X^2+0.1=1
x^2=0.9
x1-√0.9
x2=-√0.9
√(0.9)* (-√0.9)=-0.9
0 votes
Thanks 0
reshator2000
а я совсем забыл про произведение
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Answers & Comments
Verified answer
log_π (x^2+0,1)=0(x^2+0,1)=π⁰
х²+0,1=1
х²=1-0,1=0,9
х₁;₂=+/-√0,9
х₁*х₂=√0,9*(-√0,9)= -0,9
Verified answer
X^2+0.1=1x^2=0.9
x1-√0.9
x2=-√0.9
√(0.9)* (-√0.9)=-0.9