Ответ:
(1-i)*(1+i)=1-i+i+1= 2
(3+2i)*(1+i)= 3+3i+2i-2= 1+5i
(6+4i)*3i= 18i-12
(2-3i)*(-5i)= -10i-15
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Ответ:
(1-i)*(1+i)=1-i+i+1= 2
(3+2i)*(1+i)= 3+3i+2i-2= 1+5i
(6+4i)*3i= 18i-12
(2-3i)*(-5i)= -10i-15