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VSIIVIVN
@VSIIVIVN
July 2022
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Производная функции.
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Lesben
F(x)=2sinx²-cos²x-2
f´(x)=2cosx² . 2x -2cosx.(-sinx)=4xcosx²+2cosxsinx=4xcosx²+sin2x
(sinx)´=cosx, (cosx)´=-sinx, 2sinxcosx=sin2x,c´=0, (f(g(x))´=f´(g(x) . g´(x)
(sinx², f=sint, t=x², (sinx²)´=cost. (x²)´=cosx². 2x=2xcosx²)
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VSIIVIVN
Попытаюсь понять решение, большое вам спасибо!
let5
Дифференцирование сложной функции
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Answers & Comments
f´(x)=2cosx² . 2x -2cosx.(-sinx)=4xcosx²+2cosxsinx=4xcosx²+sin2x
(sinx)´=cosx, (cosx)´=-sinx, 2sinxcosx=sin2x,c´=0, (f(g(x))´=f´(g(x) . g´(x)
(sinx², f=sint, t=x², (sinx²)´=cost. (x²)´=cosx². 2x=2xcosx²)