y'=((x³+x²+1)⁸)'=8(x³+x²+1)⁷(x³+x²+1)'=8(x³+x²+1)⁷(3x²+2x)
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y'=((x³+x²+1)⁸)'=8(x³+x²+1)⁷(x³+x²+1)'=8(x³+x²+1)⁷(3x²+2x)