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Маргоша0335
@Маргоша0335
August 2022
1
4
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Прорешайте начиная с "Варинт 2"... Сколько сможете
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nKrynka
Решение
11√x - 4x - 6 ≥ 0
√x = t
4t² - 11t + 6 ≤ 0
D = 121 - 4*4*6 = 25
t₁ = (11 - 5)/8
t₁ = 6/8
t₁ = 3/4
t₂ =
(11 + 5)/8
t
₂ = 2
1)
√x = 3/4
x
₁
= 9/16
2)
√x = 2
x
₂
= 4
x
∈ [9/16; 4]
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Answers & Comments
11√x - 4x - 6 ≥ 0
√x = t
4t² - 11t + 6 ≤ 0
D = 121 - 4*4*6 = 25
t₁ = (11 - 5)/8
t₁ = 6/8
t₁ = 3/4
t₂ = (11 + 5)/8
t₂ = 2
1) √x = 3/4
x₁ = 9/16
2) √x = 2
x₂ = 4
x ∈ [9/16; 4]