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kristocka
@kristocka
July 2022
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ПРОШУ ПОМОГИТЕ
Определите при каких значениях а уравнение:
х² + 2х + 16а = 0
Имеет два различных корня
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sedinalana
Verified answer
X²+2x+16a=0
D=4-64a>0
64a<4
a<1/16
a∈(-∞;1/16)
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Verified answer
X²+2x+16a=0D=4-64a>0
64a<4
a<1/16
a∈(-∞;1/16)