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NA1966
@NA1966
September 2021
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Прошу помощи .9 класс . Тема Формулы приведения. Номер 340 а) и б).
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340 а)))
используемые формулы:
sin(-x) = -sin(x)
sin(pi/2 + x) = cos(x)
sin(pi/2 - x) = cos(x)
sin(pi/2) = 1
получим:
-cos(x) + 1 = cos(x)
1 = 2cos(x)
cos(x) = 1/2 => sin(x) = V3/2
340 b)))
sin(2pi - x) = sin(-x) = -sin(x)
cos(pi - x) = -cos(x)
sin(3pi/2 - x) = -cos(x)
получим:
sin(x) * cos(x) + (cos(x))^2 = 0
cos(x) = 0
sin(x) + cos(x) = 0
tg(x) + 1 = 0
tg(x) = -1
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Answers & Comments
Verified answer
340 а)))используемые формулы:
sin(-x) = -sin(x)
sin(pi/2 + x) = cos(x)
sin(pi/2 - x) = cos(x)
sin(pi/2) = 1
получим:
-cos(x) + 1 = cos(x)
1 = 2cos(x)
cos(x) = 1/2 => sin(x) = V3/2
340 b)))
sin(2pi - x) = sin(-x) = -sin(x)
cos(pi - x) = -cos(x)
sin(3pi/2 - x) = -cos(x)
получим:
sin(x) * cos(x) + (cos(x))^2 = 0
cos(x) = 0
sin(x) + cos(x) = 0
tg(x) + 1 = 0
tg(x) = -1