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passiveobserve
@passiveobserve
June 2022
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Прошу помощи, нужно 3 и 5 задание
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kirichekov
Verified answer
3. 5cos(β/2)-4ctg(β/2)*sin(β/2)=5cos(β/2)-4*(cos(β/2)/sin(β/2))*sin(β/2)=5cos(β/2)-4cos(β/2)=
cos(β/2)
5. tg⁵α*cos³α/(1+tg²α)=(sinα/cosα)⁵*cos³α/(1/cos²α)=(sinα/cosα)⁵ *cos³α*cos²α=(sinα/cosα)⁵ *cos⁵α=
sin⁵α
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3. 5cos(β/2)-4ctg(β/2)*sin(β/2)=5cos(β/2)-4*(cos(β/2)/sin(β/2))*sin(β/2)=5cos(β/2)-4cos(β/2)=cos(β/2)5. tg⁵α*cos³α/(1+tg²α)=(sinα/cosα)⁵*cos³α/(1/cos²α)=(sinα/cosα)⁵ *cos³α*cos²α=(sinα/cosα)⁵ *cos⁵α=sin⁵α