Прощу помощи с производными. Created by PizzaOneLove. algebra-ru

Прощу помощи с производными...

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$\displaystyle\bf\\y=Ctg3x\\\\y'=(Ctg3x)'=-\frac{1}{Sin^{2} 3x} \cdot(3x)'=-\frac{3}{Sin^{2} 3x}\\\\\\y'(x_{0} )=y'\Big(\frac{\pi }{2} \Big)=-\frac{3}{Sin^{2} (3\cdot\frac{\pi }{2}) } =-\frac{3}{Sin^{2} \frac{3\pi }{2} } =-\frac{3}{(-1)^{2} } =-3$

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PizzaOneLove Спасибо!

table123

Ответ: -3

Объяснение:

(сtgx)'= -1/sin^2 x, (ctg 3x)'=-1/sin^2 (3x) *(3x)'= -3/sin^2 (3x)

sin^2(3*p/2)=(-1)^2=1, y'( p/2)=-3/1=-3

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