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loloTRY
@loloTRY
July 2022
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agleia
X^3+2x^2-4x-8=0;
(x^3-4x)+(2x^2-8)=0;
x(x^2-4)+2(x^2-4)=0;
(x+2)(x^2-4)=0;
1)x1=-2 2)x^2=4
x2=-2 x3=2
x1+x2+x3=-2-2+2=-2
2 votes
Thanks 1
яВиктория
Корни данного уравнения:
Х1= -2,003
Х2= 2
Х3= -1,997
Сумма корней равна:
-2,003+2+(-1,997)=-2
2 votes
Thanks 0
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Answers & Comments
(x^3-4x)+(2x^2-8)=0;
x(x^2-4)+2(x^2-4)=0;
(x+2)(x^2-4)=0;
1)x1=-2 2)x^2=4
x2=-2 x3=2
x1+x2+x3=-2-2+2=-2
Х1= -2,003
Х2= 2
Х3= -1,997
Сумма корней равна:
-2,003+2+(-1,997)=-2