arc sin (-1/2) = - π/6
arc cos (√2/2)=π/4
a) arc sin (-) + 2 arc cos () =-+2·=-+ ==
б) = cos (2·(-))= cos(-)=-
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arc sin (-1/2) = - π/6
arc cos (√2/2)=π/4
a) arc sin (-
) + 2 arc cos (
) =-
+2·
=-
+
=
=
б) = cos (2·(-
))= cos(-
)=-