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Рома13OO
@Рома13OO
August 2022
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проверь себя Алгебра 8 класс стр 106
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m11m
Verified answer
1.
1) 7 и √48
√49 > √48
2) 2√3 и 3√2
√12 < √18
2.
1) √(81*49)=√81 * √49=9*7=63
2) √(0.3*120)=√(0.3*10*12)=√(3*12)=√36=6
3)
√125
=
√(25*5)
=
√25 * √5
= √25 =5
√5 √5 √5
4) √(2 ¹/₄) = √(⁹/₄) = 3/2 = 1.5
5) √(-17)² =|-17|=17
6) не видно
3.
1) 3√8 + √2 - 3√18 = 3√(4*2) + √2 - 3√(9*2)=
=3*2√2 + √2 - 3*3√2 = 6√2 + √2 - 9√2 = -2√2
2) (√5 - √2)² = (√5)² - 2√5 * √2 +(√2)² = 5-2√10+2=7-2√10
3) (2-√3)(2+√3)=2² - (√3)²=4-3=1
4. √(8а³) = √(2² * 2 * а² * а) = 2а√(2а)
5.
1)
х² -3
=
(х-√3)(х+√3)
= х-√3
х+√3 х+√3
2)
√х + √у
=
√х + √у
=
1
х-у (√х+√у)(√х-√у) √х-√у
6.
1)
5
=
5*√7
=
5√7
√7 √7*√7 7
2)
1
=
2-√3
=
2-√3
=
2- √3
= 2-√3
2+√3 (2+√3)(2-√3) 2² - (√3)² 4-3
37 votes
Thanks 117
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Answers & Comments
Verified answer
1.1) 7 и √48
√49 > √48
2) 2√3 и 3√2
√12 < √18
2.
1) √(81*49)=√81 * √49=9*7=63
2) √(0.3*120)=√(0.3*10*12)=√(3*12)=√36=6
3) √125 = √(25*5) = √25 * √5 = √25 =5
√5 √5 √5
4) √(2 ¹/₄) = √(⁹/₄) = 3/2 = 1.5
5) √(-17)² =|-17|=17
6) не видно
3.
1) 3√8 + √2 - 3√18 = 3√(4*2) + √2 - 3√(9*2)=
=3*2√2 + √2 - 3*3√2 = 6√2 + √2 - 9√2 = -2√2
2) (√5 - √2)² = (√5)² - 2√5 * √2 +(√2)² = 5-2√10+2=7-2√10
3) (2-√3)(2+√3)=2² - (√3)²=4-3=1
4. √(8а³) = √(2² * 2 * а² * а) = 2а√(2а)
5.
1) х² -3 = (х-√3)(х+√3) = х-√3
х+√3 х+√3
2) √х + √у = √х + √у = 1
х-у (√х+√у)(√х-√у) √х-√у
6.
1) 5 = 5*√7 = 5√7
√7 √7*√7 7
2) 1 = 2-√3 = 2-√3 = 2- √3 = 2-√3
2+√3 (2+√3)(2-√3) 2² - (√3)² 4-3