Дано:
LiH
------------
ω(Li)-?
ω(H)-?
Решение:
Mr(LiH)=7+1=8
ω(Li)=7÷8=0,875 ω%(Li)=ω(Li)×100%=0,875×100%=87,5%
ω(H)=1÷8=0,125 ω%(H)=ω(H)×100%=0,125×100%=12,5%
CrO₃
-----------
ω(Cr)-? ω(O)-?
Mr(CrO₃)=52+16x3=52+48=100
ω(Cr)=52÷100=0,52 ω%(Cr)=ω(Cr)×100%=0,52×100%=52%
ω(O)=48÷100=0,48 ω%(O)=ω(O)×100%=0,48×100%=48%
C₆H₁₀
-------------
ω(C)-? ω(H)-?
Mr(C₆H₁₀)=12x6+1x10=72+10=82
ω(C)=72÷82=0,878 ω%(C)=ω(C)×100%=0,878×100%=87,8%
ω(H)=10÷82=0,122 ω%(H)=ω(H)×100%=0,122×100%=12,2%
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Дано:
LiH
------------
ω(Li)-?
ω(H)-?
Решение:
Mr(LiH)=7+1=8
ω(Li)=7÷8=0,875 ω%(Li)=ω(Li)×100%=0,875×100%=87,5%
ω(H)=1÷8=0,125 ω%(H)=ω(H)×100%=0,125×100%=12,5%
Дано:
CrO₃
-----------
ω(Cr)-? ω(O)-?
Mr(CrO₃)=52+16x3=52+48=100
ω(Cr)=52÷100=0,52 ω%(Cr)=ω(Cr)×100%=0,52×100%=52%
ω(O)=48÷100=0,48 ω%(O)=ω(O)×100%=0,48×100%=48%
Дано:
C₆H₁₀
-------------
ω(C)-? ω(H)-?
Mr(C₆H₁₀)=12x6+1x10=72+10=82
ω(C)=72÷82=0,878 ω%(C)=ω(C)×100%=0,878×100%=87,8%
ω(H)=10÷82=0,122 ω%(H)=ω(H)×100%=0,122×100%=12,2%