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vanodrakon365
@vanodrakon365
July 2022
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Прямая у=7х-5 параллельна касательной к функции у=x^2+6x-8. Найдите абциссу точки касания.
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армения20171
Y=7x-5
y=x²+6x-8
y'=2x+6
k=y'(x0)
2x0+6=7
2x0=1
x0=1/2
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Answers & Comments
y=x²+6x-8
y'=2x+6
k=y'(x0)
2x0+6=7
2x0=1
x0=1/2