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veselaya7metla
@veselaya7metla
July 2022
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Прямолинейное движение точки описывается законом s=t^4-2t^2
(м). Найдите ее скорость в момент времени t=3 с
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Nurzhigitge00
V (t)=s' (t)
V (t)=(t^4-2t^2)'=4t^3-4t
V (3)=4×3^3-4×3=108-12=96
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Answers & Comments
V (t)=(t^4-2t^2)'=4t^3-4t
V (3)=4×3^3-4×3=108-12=96