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stlnsnlrry
@stlnsnlrry
August 2022
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Пусть a+b=7, ab=2. Найдите:
A) a^3+b^3;
B) a^3*b^6+a^6*b^3;
C) a^4+b^4
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kratgv
Verified answer
A+b=7, ab=2
(a+b)²=a²+2ab+b²=a²+b²+2·2=49
a²+b²=49-4=45
A) a^3+b^3=(a+b)(a²-ab+b²)=7·(45-2)=7·43=301;
B) a^3*b^6+a^6*b^3=a³b³(a³+b³)=2³·301=8·301=2408;
C) a^4+b^4(a²+b²)²=a^4+2a²b²+b^4=45²
a^4+b^4=45²-2a²b²=2025-8=2017
2 votes
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kratgv
Отметь ответ лучшим!
kratgv
:)
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Answers & Comments
Verified answer
A+b=7, ab=2(a+b)²=a²+2ab+b²=a²+b²+2·2=49
a²+b²=49-4=45
A) a^3+b^3=(a+b)(a²-ab+b²)=7·(45-2)=7·43=301;
B) a^3*b^6+a^6*b^3=a³b³(a³+b³)=2³·301=8·301=2408;
C) a^4+b^4(a²+b²)²=a^4+2a²b²+b^4=45²
a^4+b^4=45²-2a²b²=2025-8=2017