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rubinсhampion
@rubinсhampion
July 2022
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Пусть х1 и х2- корни уравнения (x-2)^2+24=(2+3*x)^2. Тогда (х1+х2)*(-6) равно:
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MrsRasta
Х²-4х+4+24=4+12х+9х²
9х²-х²+12х+4х+4-4-24=0
8х²+16х-24=0
Д=256+786=1024
х1=(-16+32)/16=1
х2=(-16-32)/16= -3
(1-3)*(-6)= -2*(-6)=
12
1 votes
Thanks 5
99tasha
Verified answer
(x-2)² +24 = (2+3x)²
X²-4x+4+24=4+12x+9x²
8x²+16x-24=0
x²+2x-3=0
D=4+12=16=4²
x1=1 x2=-3
Тогда (x1+x2)*(-6)=(1-3)*(-6)=(-2)*(-6)=12
3 votes
Thanks 7
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Answers & Comments
9х²-х²+12х+4х+4-4-24=0
8х²+16х-24=0
Д=256+786=1024
х1=(-16+32)/16=1
х2=(-16-32)/16= -3
(1-3)*(-6)= -2*(-6)=12
Verified answer
(x-2)² +24 = (2+3x)²X²-4x+4+24=4+12x+9x²
8x²+16x-24=0
x²+2x-3=0
D=4+12=16=4²
x1=1 x2=-3
Тогда (x1+x2)*(-6)=(1-3)*(-6)=(-2)*(-6)=12