P(v) + Cl (1) =
Cr(III) + O2 =
N2(III) + H2=
Li+ S(II) =
H2 + O2 =
Al + O2 =
Na + O2 =
H2 + S(II) =
К+ Н2=
Ba + O2 =
Fe(III) + 02=
Mn(VII) + O2 =
Cr(III) + O2 =
N2(III) + H2=
Li+ S(II) =
H2 + O2 =
Al + O2 =
Na + O2 =
H2 + S(II) =
К+ Н2=
Ba + O2 =
Fe(III) + 02=
Mn(VII) + O2 =
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Answers & Comments
2P+5Cl2=>2PCl5
2Cr+3O2=>2CrO3
N2+3H2=>2NH3
2Li+S=>Li2S
2H2+O2=>2H2O
4Al+3O2=>2Al2O3
4Na+O2=>2Na2O
H2+S=>H2S
2K+H2=>2KH
2Ba+O2=>2BaO
4Fe+3O2=>2Fe2O3;
4Mn+7O2=>2Mn2O7