1) х2-12х+11=0
Д=b2-4ac=(-12)2 -4*1*11=144-44=100=(10)2
x1,2=(12+-10)/2
x первое =22/2=11
x второе = 2/2=1
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
1) х2-12х+11=0
Д=b2-4ac=(-12)2 -4*1*11=144-44=100=(10)2
x1,2=(12+-10)/2
x первое =22/2=11
x второе = 2/2=1
Д=b2-4ac=(-15)2 -4*1*56=225-224=1
x1,2=(15+-1)/2
x первое = 16/8=2
x второе = 14/2=7
Д=b2-4ac=(7)2-4*6*(-3)=49+72=121=(11)2
x1,2= (-7+-11)/2*6
х первое = -28/12= - 7/3
х второе = 4/12 = 1/3