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gendriki
@gendriki
July 2022
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расчитай количество вещества хлора, необходимого для сжигания железа, массой 7,84г по схеме Fe+Cl2=FeCl3
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kanopuss
2Fe+3Cl2=2FeCl3
n(Fe) 7.84/56=0.14
n(Cl2)=014/2=x/3
n(Cl2) = 0.21
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Answers & Comments
n(Fe) 7.84/56=0.14
n(Cl2)=014/2=x/3
n(Cl2) = 0.21