4(3-a)+(n-5)×(-3)=12-4a+n-5×(-3)=12-4a+n+15=27-4a+n
Ответ:
12-4а-3n+15=27-4a-3n
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4(3-a)+(n-5)×(-3)=12-4a+n-5×(-3)=12-4a+n+15=27-4a+n
Ответ:
12-4а-3n+15=27-4a-3n