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sokol4115
@sokol4115
July 2022
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Раскройте модуль
1) |π:4 - 0,7|
2) |π:4 - 0,8|
3) |π - 3,15|
4) |x в 4 степени + 2|
5) |x во 2 степени + x + 1:4|
6) |x во 2 степени +4x +5|
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Удачник66
Решение смотри на фото
1 votes
Thanks 1
Удачник66
Ой, забыл в 5) в конце (x + 1/2)^2
ВладимирБ
Verified answer
Π=3,14; Π/4=0,78, поэтому
1) |Π/4 - 0,7| = Π/4 - 0,7
2) |Π/4 - 0,8| = 0,8 - Π/4
3) |Π - 3,15| = 3,15 - Π
4) |x^4 + 2| = x^4 + 2
5) |x^2 + x + 1/4| = |(x + 1/2)^2| = (x + 1/2)
6) |x^2 + 4x + 5| = |x^2 + 4x + 4 + 1| = |(x + 2)^2 + 1| = (x + 2)^2 + 1
4 votes
Thanks 1
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Answers & Comments
Verified answer
Π=3,14; Π/4=0,78, поэтому1) |Π/4 - 0,7| = Π/4 - 0,7
2) |Π/4 - 0,8| = 0,8 - Π/4
3) |Π - 3,15| = 3,15 - Π
4) |x^4 + 2| = x^4 + 2
5) |x^2 + x + 1/4| = |(x + 1/2)^2| = (x + 1/2)
6) |x^2 + 4x + 5| = |x^2 + 4x + 4 + 1| = |(x + 2)^2 + 1| = (x + 2)^2 + 1