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yastrebovaira
@yastrebovaira
August 2022
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Расписать электролиз раствора AgNO3
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npiecology
Verified answer
4AgNO3+2H2O=4Ag+4HNO3+O2
катод:Ag+ +e=Ag0
анод:2Н2О-4е=О2+4Н+
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Answers & Comments
Verified answer
4AgNO3+2H2O=4Ag+4HNO3+O2катод:Ag+ +e=Ag0
анод:2Н2О-4е=О2+4Н+