Расположите оксиды в порядке увеличения в них массовой доли кислорода:
1) CO; 2) CO2; 3) H2O; 4) MgO; 5) Li2O; 6) SO3
1) CO; 2) CO2; 3) H2O; 4) MgO; 5) Li2O; 6) SO3
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Ответ:
MgO , Li2O , CO , SO3 , CO2 , H2O
W(O) = Ar(O) * n / M(MgO) * 100% = 16 / 40 * 100% = 40%
W(O) = Ar(O) * n / M(Li2O) * 100% = 16 / 30 * 100% = 53.33%
W(O) = Ar(O) * n / M(CO) * 100% = 16 / 28 * 100% = 57.14%
W(O) = Ar(O) * n / M(SO3) * 100% = 16 * 3 / 80 * 100% = 60%
W(O) = Ar(O) * n / M(CO2) * 100% = 16 * 2 / 44 * 100% = 72.73%
W(O) = Ar(O) * n / M(H2O) * 100% = 16 / 18 * 100% = 88.9%
Объяснение: