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semen17112000
@semen17112000
June 2022
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Рассчитайте количество углекислого газа, содержащего 1.6 * 10 в 23 степени молекул
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Pavetta
N(CO2)=N/Na=1.6*10²³/6*10²³=0.267 моль
m(CO2)=M*n=44*0.267=11.784 г
Ответ: 11.784 г
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Answers & Comments
m(CO2)=M*n=44*0.267=11.784 г
Ответ: 11.784 г