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redson12
@redson12
July 2022
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Рассчитайте массовую долю корбаната натрия и сульфата серебра
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krioira
Mr(Na2CO3) = 2*23+12+3*16= 106
W(Na)= 46/106= 0.43=43%
W(C)=12/106=0.11=11%
W(O)=48/106=0.46=46%
Mr(Ag2SO4)=2*108+32+4*16=312
W(Ag)=216/312=0.69=69%
W(S)=32/312=0.10=10%
W(O) = 64/312=0.21=21%
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anassstass
Na2CO3
M (Na2CO3) = 46 + 12 + 48 = 106 г/моль
масс. доля Na = 46 / 106 • 100% = 43,4%
масс. доля C = 12 / 106 • 100% = 11,3%
масс. доля O = 48 / 106 • 100% = 45,3%
Ag2SO4
M (Ag2SO4) = 108 • 2 + 32 + 64 = 312 г/моль
масс. доля Ag = 216 / 312 • 100% = 69,2%
масс. доля S = 32 / 312 • 100% = 10,3%
масс. доля O = 64 / 312 • 100% = 20,5%
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Answers & Comments
W(Na)= 46/106= 0.43=43%
W(C)=12/106=0.11=11%
W(O)=48/106=0.46=46%
Mr(Ag2SO4)=2*108+32+4*16=312
W(Ag)=216/312=0.69=69%
W(S)=32/312=0.10=10%
W(O) = 64/312=0.21=21%
M (Na2CO3) = 46 + 12 + 48 = 106 г/моль
масс. доля Na = 46 / 106 • 100% = 43,4%
масс. доля C = 12 / 106 • 100% = 11,3%
масс. доля O = 48 / 106 • 100% = 45,3%
Ag2SO4
M (Ag2SO4) = 108 • 2 + 32 + 64 = 312 г/моль
масс. доля Ag = 216 / 312 • 100% = 69,2%
масс. доля S = 32 / 312 • 100% = 10,3%
масс. доля O = 64 / 312 • 100% = 20,5%