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niknikitos111
@niknikitos111
December 2021
1
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ассчитайте массу и количество вещества 6*10^23 молекул CO2
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TheMrChernik
N=N/NA=6*10^23 молекул/6.02*10^23 молекул/моль=0,9967 моль~1 моль
m(CO2)=n*M=44 г/моль *0,9967 моль=43,8548 г~44г
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m(CO2)=n*M=44 г/моль *0,9967 моль=43,8548 г~44г