n(H2S)=(3,636×10²³):(6,02×10²³)≈0,6моль
V(H2S)=0,6×22,4=13,44литра
m(H2S)=0,6×34=20,4г
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n(H2S)=(3,636×10²³):(6,02×10²³)≈0,6моль
V(H2S)=0,6×22,4=13,44литра
m(H2S)=0,6×34=20,4г