Дано:
m(Na2SO4)=200г
w(Na2SO4)=7.2%
m(BaSO4)-?
Решение:
Na2SO4+BaCl2=BaSO4+2NaCl
mв-в(Na2SO4)=200*0.072=14.4г
n(Na2SO4)=m/M=14.4/142=0.1 моль
n(Na2SO4)/1=n(BaSO4)/1
n(BaSO4)=0.1 моль
m(BaSO4)=m*M=0.1*233=23.3г
Ответ:m(BaSO4)=23.3г
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Дано:
m(Na2SO4)=200г
w(Na2SO4)=7.2%
m(BaSO4)-?
Решение:
Na2SO4+BaCl2=BaSO4+2NaCl
mв-в(Na2SO4)=200*0.072=14.4г
n(Na2SO4)=m/M=14.4/142=0.1 моль
n(Na2SO4)/1=n(BaSO4)/1
n(BaSO4)=0.1 моль
m(BaSO4)=m*M=0.1*233=23.3г
Ответ:m(BaSO4)=23.3г