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Ответ:

дано

n(AgCL) = 0.75 mol

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m(NaCL)-?

m(AgNO3)-?

NaCL+AgNO3-->AgCL+NaNO3

n(AgCL) = n(NaCL) = n(AgNO3)= 0.75 mol

M(NaCL) = 58.5 g/mol

m(NaCL) = n*M = 0.75 * 58.5 = 43.875 g

M(AgNO3) = 170 g/mol

m(AgNO3) = n*M = 0.75 * 170 = 127.5 g

ответ 43.875 г , 127.5 г

Объяснение: