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Kent56789
@Kent56789
November 2021
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Рассчитайте pH 0,1М растворов: NH3
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mrvladimir2
Verified answer
См(NH4OH) = 0,1М или 0,1 моль/л
Кд(NH4OH) = 1.79*10⁻⁵
Найти:
рН(NH3OH)-?
[/tex]
[tex]pOH=-lg[OH^{-}] = -lg1.34*10^{-3} = 2.87 ≈ 2,9
pH = 14 - 2.9 = 11,1
Ответ: 11,1
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Answers & Comments
Verified answer
См(NH4OH) = 0,1М или 0,1 моль/лКд(NH4OH) = 1.79*10⁻⁵
Найти:
рН(NH3OH)-?
[/tex]
[tex]pOH=-lg[OH^{-}] = -lg1.34*10^{-3} = 2.87 ≈ 2,9
pH = 14 - 2.9 = 11,1
Ответ: 11,1