Литий - 7, бор - 11, кислород - 16
M(Li)=7, M(B)=11, M(O)=16.
M(Li3BO3)7*3+11*1+16*3=21+11+48=80
ω(Li3/Li3BO3)=21/80=26%
ω(B/Li3BO3)=11/80=14%
ω(O3/LiBO3)=48/80=60%
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Литий - 7, бор - 11, кислород - 16
M(Li)=7, M(B)=11, M(O)=16.
M(Li3BO3)7*3+11*1+16*3=21+11+48=80
ω(Li3/Li3BO3)=21/80=26%
ω(B/Li3BO3)=11/80=14%
ω(O3/LiBO3)=48/80=60%