m(прим)=50×0,13=6,5г
m(Al)=50-6,5=43,5г
n(Al)=43,5:27=1,6
1,6. x
Al+2H2
x=3,2
V=3,2×22,4=71,68 л
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m(прим)=50×0,13=6,5г
m(Al)=50-6,5=43,5г
n(Al)=43,5:27=1,6
1,6. x
Al+2H2
x=3,2
V=3,2×22,4=71,68 л