1,068 х
Zn+H2O-->ZnO+H2
m(прим.)=78×0,11=8,58г
m(Zn)=78-8,58=69,42г
n(Zn)=69,42:65=1,068моль
х=1,068×1:1=1,068моль
V=1,068×22,4=23,9232 л
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1,068 х
Zn+H2O-->ZnO+H2
m(прим.)=78×0,11=8,58г
m(Zn)=78-8,58=69,42г
n(Zn)=69,42:65=1,068моль
х=1,068×1:1=1,068моль
V=1,068×22,4=23,9232 л