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mironovcar
@mironovcar
July 2022
2
19
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Рассчитать относительно молекулярнную массу вещества и массовые доли химических элементов в соединении
Al2O3 K2S NH3 срочно
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Answers & Comments
krioira
Mr(Al2O3) = 2*27+3*16 = 102
W(Al)=54/102 = 0.53=53%
W(O) = 48/102=0.47=47%
Mr(K2S)= 2*39+32 = 110
W(K)=78/110=0.71=71%
W(S)=32/110=0.29=29%
Mr(NH3) = 14+3*1=17
W(N)=14/17=0.82=82%
W(H)=3/17=0.18=18%
2 votes
Thanks 3
Dragomereckaya5
Mr (Al₂O₃) = 27*2 + 16*3 = 102
ω =
ω(Al) =
= 53%
ω(O) =
= 47%
Mr (K₂S) = 39*2 + 32= 110
ω =
ω(K) =
= 70,9%
ω(S) =
= 29,1%
Mr (NH₃) = 14+ 1*3 = 17
ω =
ω(N) =
= 82%
ω(H) =
=18%
1 votes
Thanks 1
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Answers & Comments
W(Al)=54/102 = 0.53=53%
W(O) = 48/102=0.47=47%
Mr(K2S)= 2*39+32 = 110
W(K)=78/110=0.71=71%
W(S)=32/110=0.29=29%
Mr(NH3) = 14+3*1=17
W(N)=14/17=0.82=82%
W(H)=3/17=0.18=18%
ω =
ω(Al) =
ω(O) =
Mr (K₂S) = 39*2 + 32= 110
ω =
ω(K) =
ω(S) =
Mr (NH₃) = 14+ 1*3 = 17
ω =
ω(N) =
ω(H) =