2V 5+ + 10 e = 2V 0 |3|
2Al 0 - 6e = 2Al 3+ |5|
3V2O5 + 10 Al = 5 Al2O3 + 6V
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2V 5+ + 10 e = 2V 0 |3|
2Al 0 - 6e = 2Al 3+ |5|
3V2O5 + 10 Al = 5 Al2O3 + 6V
Al^0 + 3e=Al^+3 | 5e восстановитель, процесс окисления
3V2O5+10Al=5Al2O3+6V