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FireDragonOfficial
@FireDragonOfficial
July 2022
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расставьте коэффициенты, получив их методом электронного баланса:
fe+hno3=fe(no3)3+n2+h2o
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VolksJugend
2N*5+ +10e=N2^0
Fe^0-3e=Fe^3+
2 votes
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2N*5+ +10e=N2^0
Fe^0-3e=Fe^3+