Х г                                                                           0,02л

  2Ag           +         2H2SO4      =    Ag2SO4     +     SO2    +   2H2O

n = 2 моль                                                              n = 1 моль

М = 108 г/моль                                                     Vm=22,4 л/моль

m=216 г                                                                 V = 22,4 л

Х г Ag       -      0,02 л SO2

216 г Ag    -    22,4 л SO2

m(Ag) = 216 * 0,02 / 22,4 = 0,19 г