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Pupil15
@Pupil15
August 2021
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Корень из 3x+1/x-1 больше/равно2
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sedinalana
метод интервалов указывает на промежутки (-∞;
]∪(1;+∞)
2 votes
Thanks 1
kensakutori
Verified answer
√[(3x+1)/(x-1)]≥2
возведем в квадрат
(3x+1)/(x-1)≥4
(3x+1)/(x-1)-4≥0
(3x+1-4x+4)/(x-1)≥0
(5-x)/(x-1)≥0
x=5 x=1
_ + _
--------------(1)-----------(5)-----------
x∈(1;5]
2 votes
Thanks 0
kensakutori
забыл про корень ://
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Answers & Comments
метод интервалов указывает на промежутки (-∞;]∪(1;+∞)
Verified answer
√[(3x+1)/(x-1)]≥2возведем в квадрат
(3x+1)/(x-1)≥4
(3x+1)/(x-1)-4≥0
(3x+1-4x+4)/(x-1)≥0
(5-x)/(x-1)≥0
x=5 x=1
_ + _
--------------(1)-----------(5)-----------
x∈(1;5]