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labzaekaterina
@labzaekaterina
July 2022
1
13
Report
Разлажите на множители
11m²-11
6a³-6a
5x³-5xy²
8a²b²-72a²c²
2x²+24xy+72a²c²
РЕШИТЕ 7 КЛАСС
ДАЮ 50 БАЛЛОВ
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Answers & Comments
Rotkappchen
11m²-11=11(m-1)(m+1)
6a³-6a = 6a(a-1)(a+1);
5x³-5xy²=5x(x-y)(x+y);
8a²b²-72a²c²=8a
²(b-3c)(b+3c);
2x²+24xy+72a²c²=2(x
²+6xy+36)=2(x+6)².
5 votes
Thanks 3
labzaekaterina
Спасибо :)
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Answers & Comments
6a³-6a = 6a(a-1)(a+1);
5x³-5xy²=5x(x-y)(x+y);
8a²b²-72a²c²=8a²(b-3c)(b+3c);
2x²+24xy+72a²c²=2(x²+6xy+36)=2(x+6)².