разложение на множители ax+bx-ay-by+az+bz
х(a+b)-y(a+b)+z(a+b)=(a+b)(x-y+z)
ах+bx-ay-by+az+bz=х(a+b)-y(a+b)+z(a+b)=(a+b)(x-y+z)
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х(a+b)-y(a+b)+z(a+b)=(a+b)(x-y+z)
ах+bx-ay-by+az+bz=х(a+b)-y(a+b)+z(a+b)=(a+b)(x-y+z)