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RussianT
@RussianT
June 2022
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Разложи на множители: 0,01t^2−(t+p)^2
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miron2077
Verified answer
0,01t²−(t+p)²=(0,1t-t-p)(0.1t+t+p)=(1.1t+p)(-0.9t-p)=-
(1.1t+p)(0.9t+p)
3 votes
Thanks 2
veroshpion
Verified answer
a^2 - b^2 = (a-b) * (a+b)
0,01t^2−(t+p)^2 = (0,01t - t-p) * (0,01t +t + p) = -(0,99t + p) * (1,01t + p)
1 votes
Thanks 1
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Answers & Comments
Verified answer
0,01t²−(t+p)²=(0,1t-t-p)(0.1t+t+p)=(1.1t+p)(-0.9t-p)=-(1.1t+p)(0.9t+p)Verified answer
a^2 - b^2 = (a-b) * (a+b)0,01t^2−(t+p)^2 = (0,01t - t-p) * (0,01t +t + p) = -(0,99t + p) * (1,01t + p)