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logekmr
@logekmr
August 2021
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Разложи на множители 1−g2−2gc−c2 .
Выбери правильный ответ:
(1−g)⋅(1+c)
(1−g)⋅(1+g−2c)
(1−g−c)⋅(1+g+c)
(g−c)2
(g+c)2
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sofimalceva779
Ответ:(1−g−c)⋅(1+g+c)
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Ответ:(1−g−c)⋅(1+g+c)