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boreka
@boreka
October 2021
2
13
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Разложи на множители 1−s2−2sd−d2 .
Выбери правильный ответ:
(1−s)⋅(1+s−2d)
(1−s−d)⋅(1+s+d)
(s−d)2
(1−s)⋅(1+d)
(s+d)2
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frizon
Ответ:
(1−s−d)⋅(1+s+d)
Объяснение:
2 votes
Thanks 2
besendofek
Ответ: (1-s-d)*(1+s+d)
Решение:
1-s^2-2sd-d^2 = 1-(s^2+2sd+d^2) =
= 1-(s+d)^2 = (1-(s+d)*(1+(s+d)) = (1-s-d)*(1+s+d)
1 votes
Thanks 1
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Answers & Comments
Ответ:
(1−s−d)⋅(1+s+d)
Объяснение:
Решение:
1-s^2-2sd-d^2 = 1-(s^2+2sd+d^2) =
= 1-(s+d)^2 = (1-(s+d)*(1+(s+d)) = (1-s-d)*(1+s+d)