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arinawsqo
@arinawsqo
July 2022
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Разложи на множители 1−t2−2td−d2
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Valtyry
1-(t-d)^2 - по формуле (a-b)^2=a^2-2ab-b^2
1^2-(t-d)^2 - т,к 1=1^2
(1-(t-d))(1+(t-d)) - по формуле a^2-b^2=(a-b)(a+b)
(1-t+d)(1+t-d) - ответ
надеюсь все подробно и понятно)
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Answers & Comments
1^2-(t-d)^2 - т,к 1=1^2
(1-(t-d))(1+(t-d)) - по формуле a^2-b^2=(a-b)(a+b)
(1-t+d)(1+t-d) - ответ
надеюсь все подробно и понятно)