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lololoxa73
@lololoxa73
July 2022
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разложиье на множетели квадратный трехчлен:x^2-7x+12
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andreevnaelina
Х²-7х+12
а=1 б=-7 с=12
D=b²-4ac= 49-48=1
x1=(7+1)/2=4
x2=(7-1)/2=3
x²-7х+12=(х-4)(х-3)
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Answers & Comments
а=1 б=-7 с=12
D=b²-4ac= 49-48=1
x1=(7+1)/2=4
x2=(7-1)/2=3
x²-7х+12=(х-4)(х-3)