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Littlequeen
@Littlequeen
August 2022
1
18
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Разложиет на множители:
а) (у+а)²-4у²
б)27а³+в
в)16-(одна восемьдесят первая дробью)х⁴
г)х²-х-у²-у
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01YES
А) (у+а)²-4у²=(у+а-2у)(у+а+2у)=(а-у)(а+3у)
г) х²-х-у²-у=х²-у²-(х+у)=(х-у)(х+у)-(х+у)=(х+у)(х-у-1)
в)16-(1/81)*х⁴=(4-(х²/9))(4+(х²/9))
б) 27а³+в
³=(3а)³+в³=(3а+в)(9а²-3ав+в²)
3 votes
Thanks 2
Littlequeen
Ой 27а³+в³
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Answers & Comments
г) х²-х-у²-у=х²-у²-(х+у)=(х-у)(х+у)-(х+у)=(х+у)(х-у-1)
в)16-(1/81)*х⁴=(4-(х²/9))(4+(х²/9))
б) 27а³+в³=(3а)³+в³=(3а+в)(9а²-3ав+в²)