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Саша1789
@Саша1789
August 2022
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Разложить на множетели:а)m^2n-n+mn^2-m; m^5+m^3-m^2-m^4; X^4-x^3-x+x^2
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anmih
Verified answer
m^2n-n+mn^2-m = m(mn-1) + n(mn-1) =
(m+n)(mn-1);
m^5+m^3-m^2-m^4 = m^(3)(m^(2)+1)-m^(2)(1+m^(2)) =
(m^3 - m^2)(1+m^2)
;
X^4-x^3-x+x^2 = x^3(x-1) + x(x-1) =
(x^3 +x) (x-1)
;
2 votes
Thanks 1
Саша1789
Спасибо
anmih
:)
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Answers & Comments
Verified answer
m^2n-n+mn^2-m = m(mn-1) + n(mn-1) = (m+n)(mn-1);m^5+m^3-m^2-m^4 = m^(3)(m^(2)+1)-m^(2)(1+m^(2)) = (m^3 - m^2)(1+m^2);X^4-x^3-x+x^2 = x^3(x-1) + x(x-1) = (x^3 +x) (x-1)
;