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C00kleS
@C00kleS
October 2021
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разложить на множители 16x^3+54y^3
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оОfoxOo
2*(3*y+2*x)*(9*y^2-6*x*y+4*x^2)=
2
(3y+2x)
(9
y2
−6xy+4
x2
)
1 votes
Thanks 1
zasstf
=(2)(8x^3+27y^3)
=2{(2x)^3 + (3y)^3}
=2(2x+3y){(2x)^2 - (2x)(3y) +(3y)^2} {Using a^3+b^3 = (a+b)(a^2-ab+b^2)
=2(2x+3y){(4x^2 - 6xy +9y^2}
1 votes
Thanks 0
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Answers & Comments
=2{(2x)^3 + (3y)^3}
=2(2x+3y){(2x)^2 - (2x)(3y) +(3y)^2} {Using a^3+b^3 = (a+b)(a^2-ab+b^2)
=2(2x+3y){(4x^2 - 6xy +9y^2}