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alenamandrikova
@alenamandrikova
July 2022
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Разложить на множители 3х²+8х-3
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m11m
3х²+8х-3=0
Д=64-4*3*(-3)=100
х₁=(-8-10)/6=-3
х₂=2/6=1/3
3х²+8х-3=3(х-¹/₃)(х+3)=(3х-1)(х+3)
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Answers & Comments
Д=64-4*3*(-3)=100
х₁=(-8-10)/6=-3
х₂=2/6=1/3
3х²+8х-3=3(х-¹/₃)(х+3)=(3х-1)(х+3)